Magnetic permeability: Difference between revisions
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harmonic mean path length |
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:''μ'' = ''Lℓ'' / ''N''<sup>2</sup>''A'' | :''μ'' = ''Lℓ'' / ''N''<sup>2</sup>''A'' | ||
=== Example === | |||
[[File:Inductor 20260412~2.jpg|thumb|alt=Measuring inductance|Measuring inductance|none]] | |||
For this example, L=1.813mH, ''Φ''=102mm, ''φ''=65.5mm, A=18.25mm×19.5mm, and N=23. | |||
Problem: calculate the magnetic permeability of the material of which this core is made. | |||
=== The Biot–Savart Law for air-core inductors and coils in free space === | |||
... | |||
Latest revision as of 15:48, 21 April 2026
Calculating the magnetic permeability of a toroid core
- L = μN2A / ℓ
where L is the inductance of a winding of wire about a magnetic core, μ is the magnetic permeability of the core, N is the number of turns of wire, A is the (constant) cross-sectional area of the core and ℓ is the harmonic mean path length of magnetic flux through the core. If Φ is the outer diameter and φ is the inner diameter of a toroidal core with a rectangular cross section, then the harmonic mean path length is calculated:
- .
Now
- μ = Lℓ / N2A
Example

For this example, L=1.813mH, Φ=102mm, φ=65.5mm, A=18.25mm×19.5mm, and N=23.
Problem: calculate the magnetic permeability of the material of which this core is made.
The Biot–Savart Law for air-core inductors and coils in free space
...
